Question

tan square A - sin square= tan square A ×sin square A . prove it . This is correct question.

Answer 1

tan sq A (1-sin sq A/tan sq A)

tan sq A (1- cos sq A)

tan sq A sin sq A

just take tan common outside

Answer 2

Answer:

The proof is explained step-wise below :

Step-by-step explanation:

To Prove : tan² A - sin² A = tan² A × sin² A

Proof :

Taking L.H.S.

= tan² A - sin² A

$=\tan^2A(1-\frac{\sin^2A}{\tan^2A})\\\\=\tan^2A(1-\frac{sin^2A}{\frac{\sin^2A}{\cos^2A}})\\\\=\tan^2A (1-\frac{1}{\sec^2A})\\\\=\tan^2A(1-\cos^2A)\\\\=\tan^2A\times \sin^2A$

= R.H.S.

Hence Proved