Question

tan square theta / 1+tan square theta+cot square theta/1+cot square theta
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Answer 1

Answer:

1 is the answer

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Answer 2

Answer:

1

Step-by-step explanation:

$\frac{tan^{2}θ}{1+tan^{2}θ} + \frac{cot^{2}θ}{1+cot^{2}θ}$

converting to sin and cos and evaluating,

$=>\frac{\frac{sin^2 θ}{cos^2 θ}}{1+\frac{sin^2 θ}{cos^2 θ}} + \frac{\frac{cos^2}{sin^2 θ}}{1+\frac{cos^2 θ}{sin^2 θ}}\\=>\frac{\frac{sin^2 θ}{cos^2 θ}}{\frac{1}{cos^2 θ}} + \frac{\frac{cos^2}{sin^2 θ}}{\frac{1}{sin^2 θ}}\\\\=> sin^2 θ + cos^2 θ\\=>1$

Hope it helps, took 20 mins. to type