Question

tan square thita/1+ tan square thita + cot square thita/ 1+ cot square thita,,= 1

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Answer 1

Answer:

Step-by-step explanation:

tan^2\Theta/(1+tan^2\Theta).+.cot^2\Theta/(1+cot^2\Theta)

put cot^2\Theta=1/tan^2\Theta (since \Theta not belongs to \pi/2 and 0)  (since cot and tan functions are undefined at 0 and \pi/2 )

=tan^2\Theta  /(1+tan^2\Theta  ) + (tan^2\Theta * 1/tan^2\Theta )/(1+tan^2\Theta )

=tan^2\Theta /(1+tan^2\Theta ) +  1/(1+tan^2\Theta )

=1