Question

tan theita= 5/12 and sin theita is negative , find cos theita​

Answer 1

Step-by-step explanation:

Tan is + ve

& sin is - ve

means it must be 3 rd quadrant...

where cos is -ve

perpendicular= 5

base= 12

hence

hypotenuse= 13

hence cos (thita )=(-12/13 )

hope this will help u.......

Answer 2

Answer:

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$tan \: theta = \frac{5}{12}$

To find= cos theta

$= > ( {</strong><strong>H</strong><strong>})^{2} = ( {</strong><strong>B</strong><strong>})^{2} + ( {</strong><strong>P</strong><strong>})^{2}$

Where, perpendicular= 5 and base = 12

${</strong><strong>H</strong><strong>}^{2} = {12}^{2} + {5}^{2}$

${</strong><strong>H</strong><strong>}^{2} = 144 + 25$

${</strong><strong>H</strong><strong>}^{2} = 169$

$</strong><strong>H</strong><strong> = \sqrt{169}$

$</strong><strong>H</strong><strong> = 13$

$cos \: theta = \frac{ - 12}{13}$

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