Question

(tan theta + 2)(2tan theta + 1) = 5tan theta + 2 sec² theta......
true or false...... justify...... answer fast ​

Answer 1

Answer:

true

Step-by-step explanation:

(tan theta+2)(2tan theta+1)

= 2tan² theta+ 4 tan theta+tan theta+2

=5tan theta+2(tan²theta+1)

=5 tan theta+2sec²theta.

Answer 2

False

Justification:

L.H.S = (tan θ+2) (2 tan θ+1)

= 2 tan2 θ + tan θ + 4 tan θ + 2

= 2 tan2θ+5 tan θ+2

Since, sec2 θ – tan2 θ = 1, we get, tan2θ = sec2 θ-1

= 2(sec2 θ-1) +5 tan θ+2

= 2 sec2 θ-2+5 tan θ+2

= 5 tan θ+ 2 sec2 θ ≠R.H.S

∴, L.H.S ≠ R.H.S