Question

tan theta + cot theta =2 then sin theta =

Answer 1

Hey friend!!!

Here is your answer..

⬇️⬇️⬇️⬇️⬇️⬇️

$\tan \alpha + \cot \alpha = 2 \\ \tan\alpha + \frac{1}{ \tan \alpha } = 2 \\ { \tan}^{2} \alpha + 1 = 2 \\ { \tan }^{2} \alpha = 1 \\ \\ \tan\alpha = \frac{1}{1}$

$\sin \alpha = \frac{1}{ \sqrt{2} }$

HOPE that it will help you ✌️ ✌️

Answer 2

Good Morning!!

Tan² x - 2Tan x +1 = 0

Put Tan x = z

=>

z² - 2z + 1 = 0

=>

z² - z - z + 1 = 0

=>

z( z -1 ) -1 ( z - 1 ) = 0

=>

z = 1

=>

Tan² x = 1

Tan x = ±1

=>

x = 135° OR x = 45°

So,

Sin x = Sin 45° = 1/√2

OR

Sin x = Sin 135° = 1/√2