tan theta- cot theta=a
cos theta +sin theta=b
elimination the theta from the question...
Help.plz.
Answers
Answered by
3
HELLO DEAR,
B=TAN THETA+COT THETA
=SIN THETA/COS THETA+COS THETA/SIN THETA
=SIN^2 THETA+COS^2 THETA/SIN THETA*COS THETA
=1/SIN THETA*COS THETA
a=SIN THETA+COS THETA
b*(a^2-1)=1/SIN THETA*COS THETA(1+2SIN THETA*COS THETA-1)
=2
I HOPE ITS HELP YOU DEAR,
THANKS
B=TAN THETA+COT THETA
=SIN THETA/COS THETA+COS THETA/SIN THETA
=SIN^2 THETA+COS^2 THETA/SIN THETA*COS THETA
=1/SIN THETA*COS THETA
a=SIN THETA+COS THETA
b*(a^2-1)=1/SIN THETA*COS THETA(1+2SIN THETA*COS THETA-1)
=2
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
0
B=TAN THETA+COT THETA
=SIN THETA/COS THETA+COS THETA/SIN THETA
=SIN^2 THETA+COS^2 THETA/SIN THETA*COS THETA
=1/SIN THETA*COS THETA
a=SIN THETA+COS THETA
b*(a^2-1)=1/SIN THETA*COS THETA(1+2SIN THETA*COS THETA-1)
=2
=SIN THETA/COS THETA+COS THETA/SIN THETA
=SIN^2 THETA+COS^2 THETA/SIN THETA*COS THETA
=1/SIN THETA*COS THETA
a=SIN THETA+COS THETA
b*(a^2-1)=1/SIN THETA*COS THETA(1+2SIN THETA*COS THETA-1)
=2
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