tan theta upon sec theta -1 =tan theta + sec theta + 1 upon tan theta + sec theta - 1
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We know that
Tan^2©=sec^2-1.........(identity)
tan©xtan©=(sec©+1)(sec©-1)
tan©\(sec©-1)=sec©+1\tan©
Therefore,
By theorem of equal ratios,
tan©\sec©-1=tan©+sec©+1\sec©-1+tan©.
(note-©=theta)
Tan^2©=sec^2-1.........(identity)
tan©xtan©=(sec©+1)(sec©-1)
tan©\(sec©-1)=sec©+1\tan©
Therefore,
By theorem of equal ratios,
tan©\sec©-1=tan©+sec©+1\sec©-1+tan©.
(note-©=theta)
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