Question

TAN tita + COT tita = SEC tita * COSEC tita

Answer 1

Consider LHS
$tan\theta + cot\theta$

$\frac{Sin\theta}{Cos\theta} + \frac{Cos\theta}{Sin\theta}$

$\frac{(Sin^2\theta+Cos^2\theta)}{Cos \theta Sin\theta}$

$\frac{1}{Cos \theta Sin\theta}$

$Sec\theta Cosec\theta$