Question

Tan(x/4+0)-tan(x/4-0)=2tan2O

Answer 1

Answer:

Solution :

Solution : L.H.S.=sin(x+y)sin(x−y)

Solution : L.H.S.=sin(x+y)sin(x−y)=sinxcosy+sinycosxsinxcosy−cosxsiny

Solution : L.H.S.=sin(x+y)sin(x−y)=sinxcosy+sinycosxsinxcosy−cosxsinyDividing numerator and denominator by cosxcosy

Solution : L.H.S.=sin(x+y)sin(x−y)=sinxcosy+sinycosxsinxcosy−cosxsinyDividing numerator and denominator by cosxcosy=(sinxcosx)+(sinycosy)(sinxcosx)−(sinycosy)

Solution : L.H.S.=sin(x+y)sin(x−y)=sinxcosy+sinycosxsinxcosy−cosxsinyDividing numerator and denominator by cosxcosy=(sinxcosx)+(sinycosy)(sinxcosx)−(sinycosy)=tanx+tanytanx−tany=R.H.S