tan(x+pi)-tan(pi-x)=2tanx
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tan(π+x)-tan(π-x)
=(tanπ+tanx)/1-tanπtanx)-[(tanπ-tanx)/(1-tanπtanx)]
=(tanπ+tanx-tanπ+tanx)/(1-tanπtanx)
=2tanx/(1-0). because tanπ=0
=2tanx
=(tanπ+tanx)/1-tanπtanx)-[(tanπ-tanx)/(1-tanπtanx)]
=(tanπ+tanx-tanπ+tanx)/(1-tanπtanx)
=2tanx/(1-0). because tanπ=0
=2tanx
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