Math, asked by jiak, 1 year ago

tan (x) sin (x) + cos (x) = sec (x)​


wardahd1234: OK

Answers

Answered by Anonymous
8

sinx/cosx*sinx + cosx

=sinx/cosx*sinx + cos²x

=now sinx +cos²x= sec*cosx

=sin²x + cos²x = 1/cosx *cosx

=sin²x +cos²x =1

LHS = RHS


Anonymous: hi @bellaa
jatin3621: hii bella
rakshitverma619: hlo
OmShinde76: Ok.. so...
jatin3621: hmm
Answered by Anonymous
6

Answer:

sin²x +cos²x =1

Step-by-step explanation:

 <  >  \:  \tan =  \frac{ \sin }{ \cos } put \: it \: in \:  \tan \\  \\    =  > \frac{  \sin }{ \cos }  \times  \sin(x)  +  { \cos(x) }^{2}  =  \sec(x)  \\  \\   =  > \sin(x)  +  { \cos(x) }^{2}  =  \sin(x)  \times  \cos(x)  \\  \\   =  >  { \sin(x) }^{2}  +  { \cos(x) }^{2}  = 1


OmShinde76: Ok..
OmShinde76: So After a very long time
OmShinde76: Hope u will reply...
Similar questions