tan1°tan2°tan3°.....tan89°=x
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anant991:
your answer is correct but options are different
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If the sum of two agles is 90°. And they are attached to 'tan' then their multiplication will be 1.
For example- tan 30 . tan 60.
you can see the sum of 60 + 30 is 90. And and they are attached with tan. then their multipublication will be equal to 1.
Let's come to the question now.
A series has been given from tan 1 to tan 89. We have to look how many such pairs are there whose angles' sum is 90. And the value of those pairs will be equal to 1.
tan 1 . tan 89 = 1 ( WE already discussed it in the beginning)
tan 2 . tan 88 = 1
tan 3 . tan 87 = 1
Now we cannot keep doing it forever.
tan 44. tan 46. = 1
so we can now put it this way- -
(tan1 tan 89 ) (tan 2 tan 88) ( tan 3 tan 87.).... ..... tan 45
because there is no pair available for tan 45.
You already know the value of ( tan 1 tan 89) is 1 . So replace it with 1.
1 × 1 × 1 ..... tan 45.
tan 45
tan 45 is also 1.
so 1 is your answer.
For example- tan 30 . tan 60.
you can see the sum of 60 + 30 is 90. And and they are attached with tan. then their multipublication will be equal to 1.
Let's come to the question now.
A series has been given from tan 1 to tan 89. We have to look how many such pairs are there whose angles' sum is 90. And the value of those pairs will be equal to 1.
tan 1 . tan 89 = 1 ( WE already discussed it in the beginning)
tan 2 . tan 88 = 1
tan 3 . tan 87 = 1
Now we cannot keep doing it forever.
tan 44. tan 46. = 1
so we can now put it this way- -
(tan1 tan 89 ) (tan 2 tan 88) ( tan 3 tan 87.).... ..... tan 45
because there is no pair available for tan 45.
You already know the value of ( tan 1 tan 89) is 1 . So replace it with 1.
1 × 1 × 1 ..... tan 45.
tan 45
tan 45 is also 1.
so 1 is your answer.
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