tan15x° tan 75° x tan15° x tan 75° =
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solution
tan15°= cot(90-75°) = cot 75°
tan75°= cot(90°-15°)= cot 15°
Now, (cot75°* tan75° ) (cot15°*tan15°)
= 1*1
= 1
__________
hope it helpz☺
tan15°= cot(90-75°) = cot 75°
tan75°= cot(90°-15°)= cot 15°
Now, (cot75°* tan75° ) (cot15°*tan15°)
= 1*1
= 1
__________
hope it helpz☺
Answered by
1
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= tan 15° * tan 75° * tan 15° * tan 75°
We can write tan 15° as tan ( 90° - 75° ).
= tan ( 90° - 75° ) * tan 75° * tan ( 90° - 75° ) * tan 75°
We know that tan ( 90° - a ) = cot a
tan ( 90° - 75° ) = cot 75°.
Now,
= cot 75° * tan 75° * cot 75° * tan 75°
= cot 75° * ( 1 / cot 75° ) * cot 75° * ( 1 / cot 75° ) [ cot a = 1 / tan a ]
= 1.
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