Question

tan2π/4 + sec2π/2 - cot2π/6=2​

Answer 1

Answer:

9/2

Step-by-step explanation:

${ \tan}^{2} ( \dfrac{\pi}{4} ) + { \sec }^{2} \pi - { \cot}^{2} \dfrac{\pi}{6}$

${ (\dfrac{1}{ \sqrt{2} }) }^{2} + ( - 1) ^{2} + { (\sqrt{3}) }^{2} \\ = \dfrac{1}{2} + 1 + 3 \\ = \dfrac{9}{2}$

Answer 2

Answer is Attachment

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