Question

tan² .sec²(cot² - cos²)=​

Answer 1

Step-by-step explanation:

Given that :-

tan² A.sec²A(cot²A- cos²A)

=>tan² A.sec²Acot²A- tan² A.sec²Acos²A

We know that:-

TanA×CotA=1 and SecA×Cos A =1

=>sec²A(1)- tan² A(1)

=>sec²A- tan² A

We know that:-sec²A- tan² A=1

=>1

tan² A.sec²A(cot²A- cos²A)=1

Answer 2

Answer:

1 is the answer for your question