Math, asked by abishekcps, 9 months ago

tan²θ-sin²θ/tan²θ sin²θ what is the value of this

Answers

Answered by varad032005
1

Answer:

1

Step-by-step explanation:

tan²θ - sin²θ / tan²θ sin²θ

(sin²θ/cos²θ ) - sin²θ / tan²θ sin²θ

(sin²θ - sin²θ *cos²θ/cos²θ) / tan²θ sin²θ

[sin²θ (1-cos²θ)/cos²θ]/tan²θsin²θ   {1-cos²θ = sin²θ}

[sin²θ*sin²θ/cos²θ] / tan²θ sin²θ  { sin²θ/cos²θ =tan²θ}

sin²θtan²θ/tan²θsin²θ

1

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