tan²(theta) = csc²(theta) tan²(theta) - 1
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Answer:
Given
tan2A + cot2 A = Sec2A Cosec2A - 2
Taking L.H.S.
⇒tan2A + cot2 A
⇒Sec2A - 1 + Cosec2A - 1 ( As we know 1 + tan2A = Sec2A , 1 + cot2A = Cosec2A )
⇒Sec2A + Cosec2A - 2
⇒1Cos2A + 1Sin2A - 2
⇒Sin2A + Cos2ACos2ASin2A - 2
⇒1Cos2ASin2A - 2
⇒Sec2A Cosec2A - 2
Hence
L.H.S. = R.H.S. ( Hence proved )
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