Question

⇝tan2(x)−sin2(x)=cos2(x)sin2(x)​−sin2(x)⇝sin2(x)(cos2(x)1−cos2(x)​)⇝sin2(x)(cos2(x)sin2(x)​)⇝sin2(x)tan2(x)​ \begin{gathered} \bf⇝ \frac{1}{ \ \cos {}^{2} (x) - sin {}^{2} (x) } \\ \\ \bf⇝ \frac{1}{ \cos(2x) } = \sec(2x) \neq \: \tan {}^{2} (x) \end{gathered}⇝ cos2(x)−sin2(x)1​⇝cos(2x)1​=sec(2x)=tan2(x)​

Answer 1

Answer:

what is this ? i can't understand it sorry