Question

(tan20/cosec70)^+(cot20/sec70)^+2×tan15×tan45×tan75​

Answer 1

Answer:

hello..

(tan20/cosec70)2+(cot20/sec70)^2+2tan15tan45tan75

={tan(90-20)/cosec70}^2+{cot90-20)/sec70}^2+2(tan90-15)tan45 tan 75

=(cot70/cosec70)^2 + (tan70/sec70) ^2+ 2(cot75 tan 45 tan75 )

=(cos 70/sin70/1/sin70)^2 +(sin70/cos70/1/cos70) ^2+2(1×1)

=(cos70+sin70)^2 +2

=1+2

=3...

i hope it help you.....

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