Math, asked by prabhakarreddy4522, 9 months ago

tan20°=k,then,tan250°+tan340°÷tan20°-tan110°=

Answers

Answered by sprao53413

1

Answer:

(Cot20°-tan20°) /tan20°+cot20°

=1-tan^2 20°/1+tan^2 20°=1-k^2 /1+k^2

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