tan2a=5/12then find sin2A and cos2A
Answers
Answered by
1
Answer:
Given, tanA=
12
5
=
AB
BC
∴AC=AB
2
+BC
2
⇒AC
2
=5
2
+(12)
2
⇒AC
2
=25+144
⇒AC
2
=169
⇒AC=13
Now, sinA=
AC
BC
=
13
5
cosA=
AC
AB
=
13
12
∴sinA+cosA
=
13
5
+
13
12
=
13
5+12
=
13
17
hope it helps u....... .
Similar questions