tan2a+cot2a=sec2acosec2a-2
Answers
Answered by
2
Answer:
mark me as brainlist if this helps u
Attachments:
Answered by
0
Answer:
Step-by-step explanation:
Sin2A/cos2A+cos2A/sin2A=
(sin2A)2+(cos2A)2/sin2A×cos2A=
[a2 + b2= (a+b)2-2ab]
(sin2A+cos2A)2-2sin2A.cos2A/sin2A.cos2A
Similar questions