Physics, asked by nainak22, 9 months ago

tan²A/secA + 1 -sec A is equal to?

Answers

Answered by kritanuchatterjee280

0

Answer:

sin²A + 1 - sec A

Explanation:

tan²A/sec A + 1 -sec A

sin²A/cos²A * cos²A +1 -sec A

sin²A + 1 - sec A

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