tan2theta-sin2theta =tan2thetasin2theta
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Answered by
1
Answer:
L.H.S
tan²a-sin²a
=(sin²a/cos²a)-cos²a
=(sin²a-sin²acos²a)/cos²a
=sin²a(1-cos²a)/cos²a
=sin²a.sin²a/cos²a
=sin*4a/cos²a
R.H.S
tan²a/sin²a
=sin²a.sin²/cos²a
=sin*4a/cos²a
L.H.S=R.H.S
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