tan2x +tan3X=tanA then A=
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Answer:
∵tan3x=tan(2x+x)
⇒tan3x=
1−tan2x.tanx
tan2x+tanx
⇒tan3x−tan3xtan2xtanx=tan2x+tanx
⇒tan3x−tan2x−tanx=tan3xtan2xtanx
Step-by-step explanation:
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