Question

tan3 theta ÷tan theta -1=sec2 theta +tan theta

Answer 1

The Problem can be written astan3(theta) + tan(theta) - 2tan2(theta) = 0

Use following formulas in above equation so that all variables are in form of Tan (theta)

Tan 3A = tan (A + 2A) = ( Tan A + Tan 2A )/(1-Tan A Tan 2A)

Tan 2A = 2Tan A/(1 – Tan^2 A)