Math, asked by vikashkumar858483, 1 day ago

tan³60°+3cos²30° solve

Answers

Answered by tseries9966
1

Answer:

tan 60°=√3 so tan³60°=√3*√3*√3=3√3

Cos 30°=√3/2 so 3Cos²30°=3*√3/2*√3/2=9/4

Add them

3√3+9/4=4*3√3+1*9/4=12√3+9/4

Answered by jaswanthkondamuri420
0

3cos²30° + sec²30° + 2cos0° + 3sin90° - tan²60°

we know, cos30° = √3/2

sec30° = 1/cos30° = 2/√3

cos0° = 1 , sin90° = 1

tan60° = √3

now, 3 × (√3/2)² + (2/√3)² + 2(1)² + 3(1) - (√3)²

= 3 × 3/4 + 4/3 + 2 + 3 - 3

= 9/4 + 4/3 + 2

= 9/4 + (4 + 6)/3

= 9/4 + 10/3

= (27 + 40)/12

= 67/12

Similar questions