Math, asked by dhanush98176, 11 months ago

tan3A-tan2A-tanA=tan3A.tan2A.tanA​

Answers

Answered by sandy1816
2

Step-by-step explanation:

tan3A=tan(2A+A)

tan3A=tan2A+tanA/1-tan2AtanA

tan2A+tanA=tan3A-tan3Atan2AtanA

tan3A-tan2A-tanA=tan3Atan2AtanA

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