Question

tan3a-tan2a-tana=tan3a tan2a tana

Answer 1

Hope it helps you.....

Answer 2

Answer:

We know that,

3A = 2A + A

Hence taking tan both side,

tan 3A = tan (A+2A)

tan 3A = (tanA + tan 2A)/(1 - tanA*tan 2A)

tanA + tan 2A = tan 3A (1-tanA*tan 2A)

tanA + tan 2A = tan 3A - tanA*tan 2A*tan 3A

tan 3A - tanA - tan 2A = tanA*tan 2A*tan*3A

Hence proved