tan3x tan2x tanx = tan3x - tan2x- tanx
wasif65:
tan(x+2x) = tan(x) + tan(2x)/1-tan(x).tan(2x)
2nd step--- tan(3x)= tan(x)+tan(2x)/1-tan(x).tan(2x)
cross multiply then transport you will get the answer
thanks sar ji
you're welcome
Answers
Answered by
1
tan6x³ = 0 => tan 0° = 0 = tan 6x³
=> 6x³ = 0 => x = 0
=> 6x³ = 0 => x = 0
not right
Answered by
1
Answer: its
easy
Step-by-step explanation:
tan(x+2x) = tan(x) + tan(2x)/1-tan(x).tan(2x)
2nd step--- tan(3x)= tan(x)+tan(2x)/1-tan(x).tan(2x)
cross multiply then transport you will get the answer
Similar questions