tan3x tan2x tanx= tan3x-tan2x-tanx prove it plz do it faster
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tan3x = tan(2x+x)
tan3x = (tan2x + tanx) / (1 - tanx.tan2x)
tan3x ( 1 - tanx.tan2x) = (tan2x + tanx)
tan3x - tan3x.tan2x.tanx = tan2x + tanx
tan3x.tan2x.tanx = tan3x - tan2x - tanx
Hence provedĀ
sahi12:
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Answered by
7
Hi ,
tan ( 2x + x )
tan3x = ( tan2x + tanx ) / ( 1- tan2xtanx )
tan3x( 1 - tan2xtanx ) = tan2x + tanx
tan3x - tanxtan2xtan3x = tan2x + tanx
tan3x - tan2x - tanx = tan3x - tan2x - tanx
Hence proved.
I hope this helps you.
:)
tan ( 2x + x )
tan3x = ( tan2x + tanx ) / ( 1- tan2xtanx )
tan3x( 1 - tan2xtanx ) = tan2x + tanx
tan3x - tanxtan2xtan3x = tan2x + tanx
tan3x - tan2x - tanx = tan3x - tan2x - tanx
Hence proved.
I hope this helps you.
:)
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