Question

tan45°+cos^2(30)° - sin^2(60)°​

Answer 1

trigonometry

we know

tan 45° = 1 and sin60° = √3/2

and cos 30 = √ 3/2

then ,

$\tan(45) + \cos {}^{2} (30) - \sin {}^{2} (60)$

$= 1 + ( \frac{ \sqrt{3} }{2} ) {}^{2} - ( \frac{ \sqrt{3} }{2} ) {}^{2}$

$= 1$

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