Math, asked by shultz, 1 year ago

tan5 tan30 4tan85   is equal to

Answers

Answered by mysticd
28

Answer:

\red {Value \:of \: tan5 tan30\cdot 4tan85}\green{=\frac{4}{\sqrt{3}}}

Step-by-step explanation:

 Value \:of \: tan5 tan30 \cdot 4tan85 \\=tan(90-85) tan30 4tan85 \\=cot85 tan30 4tan85

\boxed { \pink { tan (90-A) = cotA }}

 = 4 (cot 85 tan 85) tan 30\\=4\times 1 \times \frac{1}{\sqrt{3}}

\boxed { \pink { cotA \cdot tanA = 1}}

 =\frac{4}{\sqrt{3}}

Therefore.,

\red {Value \:of \: tan5 tan30\cdot 4tan85}\green{=\frac{4}{\sqrt{3}}}

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