tan56=cos 11+sin11÷cos 11-sin11
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Hey dear here is your answer.
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hope it helps u !!
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Answer :
Now, L.H.S. = tan56
= tan (45 + 11)
= (tan45 + tan11)/(1 - tan45 tan11),
using the identity
tan(A + B) = (tanA + tanB)/(1 - tanA tanB)
= (1 + tan11)/(1 - tan11), since tan45 = 1
= (1 + sin11/cos11)/(1 - sin11/cos11),
since tanθ = sinθ/cosθ
= (cos11 + sin11)/(cos11 - sin11)
= R.H.S. [Proved]
#MarkAsBrainliest
Now, L.H.S. = tan56
= tan (45 + 11)
= (tan45 + tan11)/(1 - tan45 tan11),
using the identity
tan(A + B) = (tanA + tanB)/(1 - tanA tanB)
= (1 + tan11)/(1 - tan11), since tan45 = 1
= (1 + sin11/cos11)/(1 - sin11/cos11),
since tanθ = sinθ/cosθ
= (cos11 + sin11)/(cos11 - sin11)
= R.H.S. [Proved]
#MarkAsBrainliest
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