Question

[(Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30°

Answer 1

value of

tan60= sqrt3

cos45 = 1/sqrt2

cosec45=sqrt2

sec90=infinity

=Tan60°) ^2+4cossqare45°+4cosecsqare60°+2secsqare90°]/[2cosec30°+3sec60°-7/3cotsqare30

=Tan60°) ^2+4cossqare45°+4cosecsqare60°+infinity]/[2cosec30°+3sec60°-7/3cotsqare30

=infinity

In the given question there is sec90 whose value is infinite so the and become infinity .