Question

What is the magnitude of vector A= 2i+3j-k and B=4i-j-6k

Answer 1

Magnitude of vactor A = sqrt 2^2 + 3^2+(-1)^2 = sqrt14

magnitude of vector B = sqrt (4^2+(-1)^2+(-6)^2)= sqrt53

Answer 2

Answer:

Given it :- A = 2i+3j-k & B =4i-j-6k

magnitude of A =

$\sqrt{ {2}^{2} + {3}^{2} + {( - 1)}^{2} } = \sqrt{4 + 9 + 1 } = \\ \sqrt{14}$

magnitude of B=

$\sqrt{ {4}^{2} + {( - 1)}^{2} + {( - 6)}^{2} } = \sqrt{16 + 1 + 36 } \\ \: \: \: \: \: \: \sqrt{53}$