Chemistry, asked by vjj212887, 3 months ago

tan66° + tan69°\1- tan66°.tan69°

Answers

Answered by krishsh10kowshik
2

tan66°+tan69°-tan66°.tan69°

tan(a + b) =  \frac{tana + tanb}{1 - tanatanb}

66°+69°=135°

applying tan on both sides

tan(66°+69°)=tan135°

tan135°=tan(90°+45°)

Tan(90°+theta )lies in 2nd quadrant

in 2nd quadrant tan is negative

so,tan135°=-tan45°

tan45°=1

-tan45°=-1

tan135°=-1

tan66°+tan69°/1-tan66°tan69°=-1

so,tan66°+tan69°/1-tan66°tan69°=1

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