Math, asked by radhadwivedi656, 1 year ago

Tan7°×tan33°×tan60°×tan57°×tan83°

Answers

Answered by NiksDwivedi
0
⭐█Solution█⭐

tan7°×tan33°×tan60°×tan57°×tan83°

=> cot(90°- 7°)× cot(90° - 33°) × √3 × \dfrac{1}{cot57°}×\dfrac{1}{cot83°}

=> cot83°×cot57°×√3 × \dfrac{1}{cot57°} × \dfrac{1}{cot83°}

=> 1 × 1 × √3 × \dfrac{1}{1} × \dfrac{1}{1}

After solving this we get,

=> √3

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