Math, asked by manimahesh999, 1 year ago

TanA/1-CotA+CotA/1-TanA = 1+SecA Cosec A

Answers

Answered by TheTotalDreamer
9
Hey,

Tan a/(1-cot a) +cot a/(1-tan a)

=(sin a/,cos a) /(1-cos a/sin a) + (cos a/sin a) /(1-sin a/cos a)

=sin ^2 a/cosa(sina - cosa) +cos^2 a/sina (cosa-sina)

=sin^2a/cosa(sina-cosa) - cos^2a/sina (sina-cosa)

=(sin^3a-cos^3a)/sina.cosa(sina-cosa)

=(sina-cosa)(sin^2a+cos^2a+sinacosa)/sina.cosa(sina-cosa)

=(1+sinacosa)/sina.cosa

=(1/sinacosa)+1

=1+seca.coseca= ANSWER

HOPE IT HELPS:-))

Answered by aashreyrachaputi
9

Answer:


Step-by-step explanation:


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