Question

tanA÷1+secA+1+secA÷tana=​

Answer 1

Answer

Prove that

1+secA

tanA

−

1−secA

tanA

=2cosecA

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ANSWER

1+secA

tanA

−

1−secA

tanA

=2⋅cosecA

L.H.S

1+secA

tanA

−

1−secA

tanA

=

1−sec

2

A

tanA(1−secA)−tanA(1+secA)

=

−tan

2

A

tanA(1−secA−1−secA)

−tanA

−2secA

sinA/cosA

2⋅1/cosA

sinA

2

=2⋅cosecA

=R.H.S

∴ L.H.S=R.H.S.