Question

TanA/1+secA - tan A/1-secA =2cosecA

Answer 1

Answer:

LHS tanA (1/(1+secA)-1/(1-secA))

= tanA (1-secA-1-secA)/((1+secA)(1-secA))

=-tanA.secA.2/(1-sec^2A)

= -tanA.2.secA/(-tan^2A)

=2secA/tanA

=2(1/cosA)/(sinA/cosA)

=2/sinA

=2cosecA = RHS