Question

tanA*1 /tanA = secA*cosecA

Answer 1

LHS= tanA+1/tanA= sinA/cos+cosA/sinA
after taking lcm
sin^2+cos^2/sincos=1/sincos
1/sin= cosec
1/cos=sec
therefore, 1/sincos=cosec*sec

Answer 2

Hey There! ☺

Good Question. But there is a mistake in your question.
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Corrected Question :

tanA + (1/tanA) = secA x cosecA    [correction is in LHS sign]


Solution :

Refer the attached image.

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Hope it helped! ☺