Question

tanA=20/21,then evaluate sinA×cosA/(cosA-sinA)(cosA+sins)
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Answer 1

Answer:tanA=20/21 =p/b then h=?

using pythagoras theorem,

h^2=p^2+b^2

or, h^2=841

or h=29

now, sinA=p/h =20/29 and sinA=b/h=21/29

or, sinA*cosA/(cosA-sinA)(cosa+sinA)

or, 420/841/(21^2/29-20^2/29)

or,420/841/(41/841)

or,420/41

or,10.24

Step-by-step explanation: