(tanA+cosB)² - (cotB-secA)² =2tanA.cotB (cosB+secA
Answers
Answered by
0
Step-by-step explanation:
solving for LHS
(tan²A + cos²B + 2tanAcosB) - (cot²B + sec²A - 2cotAsecB)
Lhs: tan2A+cosec2B+2 tanA.cosecB-cot2B-sec2A+2cotB. SecA
=cosec2B-cot2B-(sec2A-tan2A)+2tanA. CosecB+2cotB. SecA
=1-1+2tanA. CosecB+2cotB. SecA
=2 (sinA/cosA × 1/sinB)+2 (cosB/sinB × 1/cosA)
=2 (sinA+cosB)/cosA.sinB
Rhs:2×sinA/cosA×cosB/sinB ×{1/SinA +1/cosB}
=2( sinA. CosB/cosA.sinB)×(cosB+sinA/sinA.cosB)
=2 (sinA+cosB)/cosA. SinB
Lhs=Rhs
Similar questions