Question

tanA=n/m so sinA=?and secA=?​

Answer 1

Answer:

tanA = Prependicular / Base = n/m

Therefore, Prependicular = n, Base = m, Hypotenuse = √(n² + m²) .

Thus, sinA = Prependicular / Hypotenuse = n/√(n² + m²) .

Thus, secA = 1/cosA = Hypotenuse / Base = √(n² + m²)/m .

Answer 2

by using Pythagorean theorem

hypotenuse=√n2+m2

sinA/coaA=n/m

on comparing both side of equation

sina=n/√n2+m2

and seca=√n2+m2/m

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