Math, asked by nitinkumar3046, 11 months ago

TanA+secA-1/TanA-SecA+1=1+sinA/cosA

Answers

Answered by bindidevi002

1

Step-by-step explanation:

LHS = tanA + secA -1 / tanA - secA + 1

= tanA + secA + tan2A - sec2A / tanA - secA + 1

as tan2A + 1 = sec2A

= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1

= tanA + secA( 1 + tanA - secA) / tanA - secA + 1

=tanA + secA

= sinA / cosA + 1/cosA

= sinA + 1 / cosA

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