Question

TanA + SecA - 1/TanA - SecA+1 = 1+ SinA / CosA...please solve ​

Answer 1

tanA + secA - 1 / tanA - secA + 1 = 1 + sinA / cosA
LHS = tanA + secA -1 / tanA - secA + 1
= tanA + secA + tan2A - sec2A / tanA - secA + 1
as tan2A + 1 = sec2A
= tanA + secA +(tanA + secA)(tanA - secA)/ tanA - secA + 1
= tanA + secA( 1 + tanA - secA) / tanA - secA + 1
=tanA + secA
= sinA / cosA + 1/cosA
= sinA + 1 / cosA
I hope it help u
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