Question

tanA-sinA upon tanA+sinA =secA-1 upon secA+1

Answer 1

I hope it helps you

Answer 2

tan A - sin A/ tan A + sin A = sec A - 1 / sec A + 1

LHS,

=(sin A / cos A - sin A)/(sin A / cos A + sin A)

=Sin A ( 1/Cos A - 1)/ Sin A ( 1/Cos A + 1)

Sin A in numerator and Sin A in denominator will be deleted

We know 1 / cos A = Sec A

so,

=Sec A -1/Sec A +1

= R.H.S

H.P