tanA+tanB+tanC = tan thita A+B+C =90° then find sin(thita-a) sin(thita-b)sin(thita-c)??
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anA=3 1, find the value of
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In triangle ABC , right - angled at B , if tanA = 1/√(3) , find the value of:(i) sinAcosC + cosAsinC (ii) cosAcosC - sinAsinC
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In ABC , B = 90^o , tan A = 1√(3) = BCAB Let BC = 1x, AB = √(3)x AC^2 = AB^2 + BC^2 AC^2 = (√(3)x)^2 + (x)^2 = 4x^2 AC = 2x (i) sin A cos C + cos ... More
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